Question

a bus starting from a rest moves with a uniform acceleration after 10min it speed is 60 kmph calculate the accelaration of the bus ​

Answer 1

Given :

▪ Initial velocity = zero

▪ Final velocity = 60kmph

▪ Time interval = 10min

To Find :

▪ Acceleration of bus.

Concept :

❇ Acceleration is defined as the rate of change in velocity.

❇ It is a vector quantity.

❇ It can be positive, negative and zero.

❇ It has both magnitude as well as direction.

❇ SI unit : m/s²

Conversion :

↗ 1kmph = 5/18mps

↗ 60kmph = 60×5/18 = 16.67mps

↗ 10min = 10×60 = 600s

Calculation :

$\dashrightarrow\sf\:a=\dfrac{v-u}{t}\\ \\ \dashrightarrow\sf\:a=\dfrac{16.67-0}{600}\\ \\ \dashrightarrow\underline{\boxed{\bf{\orange{a=0.028\:ms^{-2}}}}}\:\gray{\bigstar}$

Answer 2

$\huge{\boxed{\fcolorbox {white}{pink}{answer}}}$

$\red{u = 0}$

$\green{s = 60 {km} \: per \: hr = \frac{50}{2} m {s}^{ - 1} }$

$\purple{t = 10min = 600sec}$

$\pink{t = 10 \times 60 = 600sec}$

${ \green {\underline { \green{\underline{\green{according \: to \: 1st\: equation \: of \: motion:}}}}}}$

$\red{v = u + at}$

$\purple{so \: put \: the \: values \: down : }$

$\blue{ \frac{50}{3} = 0 + a \times 600 }$

$\green{ \frac{50}{3} = 600 a}$

$\pink{a = \frac{50}{3 \times 600} }$

$\purple{a = \frac{1}{24} }$

$\green{a = 0.041m {s}^{ - 2} }$

$<marquee > <b > <font \: color = red > follow me$

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