Question

A bus starting from rest accelerates in a straight line at a constant rate of 3m/s2
for 8s.
Calculate the distance travelled by the bus during this time interval.

Answer 1

Answer:

s = 96 m

Explanation:

GIVEN :

u = 0 m/s 

a = 3 m/s^2

t  =  8 sec

s = ?

s = ut + 1/2 at^2

s = 0*8 + 1/2*3*8*8

0   +  3*4*8

12 *8

s = 96 m

Answer 2

Answer:

96m is the total distance traveled

Explanation:

Here,

Distance (d) = ?

Time (t) = 8s

Acceleration (a) = 3m/s²

Initial velocity (u) = 0

using the 2nd Equation of Motion

⇒ s = ut + 1/2 at²

(here 's' = distance )

So, s = 0× 8 + 1/2 × 3 × (8)²

s = 0 + 1/2 ×3×64

s = 0 + (3×32) = 96 m