A bus starting from rest accelerates in a straight line at a constant rate of 3m/s² for 8s.Calculate the distance travelled by the bus during the time interval
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s=1/2at^2=1/2(3)(8^2)=32*3=96m
Answered by
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Answer:
initial velocity or (u) = 0
acceleration or (a) = 3m/s²
time (t) = 8s
therefore, s = ut + 1/2×a×t²
=>s = 0×8 + 1/2 × 3 × 8²
=>s = 0 + 1/2 × 3 × 64
=>s = 0 + 1 × 3 × 32
=>s = 96m
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