A bus starting from rest accelerates in a straight line at a constant rate of 3 m per second for 8 seconds calculate the distance travelled by the bus during this time interval
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vf=v0+atvf=v0+at and to then calculate the distance traveled using
v2f=v20+2∗a∗dvf2=v02+2∗a∗d
vf=0+3∗8ms−2∗8s=24ms−1vf=0+3∗8ms−2∗8s=24ms−1
242=02+2∗3∗d242=02+2∗3∗d
d = 576/6 = 96 meters
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