Question

A bus starting from rest attains a speed of 36 km / hr in 5s calculate acceleration and distance travelled by bus during this duration

Answer 1

Answer:

a=2 and s=25

Explanation:

given

u=0

v=36kmph=36×5/18m/s

to convert kmph to m/s multiply and divide by 5/18

w.k.t a=v-u/t

a=10-0/5

a=2m/s^2

for finding s

w.k.t s=ut+1/2at^2

since u=0

s=1/2×2×5×5

therefore s=25m