Question

a bus starting from rest attains a velocity 72km/hour in 5 minutes. if the acceleration is uniform then find the acceleration of the bus? ​

Answer 1

Answer:

Given :

Initial Velocity=u=0m/s

Final velocity= V= 72km/h

Time =5 min =5/60 h =1/12 h

acceleration=a=?

As we know that , a=v-u/t

⇒a=72-0/1/12

=72*12

=864km/h²

Distance travelled  =s=ut+1/2at²

=0x1/12 +1/2(864)(1/12)²

=(1/2)x864x(1/144)

=3km

∴Distance travelled by the train for attaining this velocity 3km.

Answer 2

Answer:

The answer is -

= 864 km/$hour^{-2}$

Explanation:

To find the acceleration of the bus

A bus starting from rest attains a velocity of 72 km/hour in 5 minutes [Given]

Follow the formula of acceleration

So,

We know that acceleration = $\frac{v - u}{t}$, where $v$ = final velocity and $u$ = initial velocity, and t = time taken

So, in the question

initial velocity = rest position

That is,

initial velocity or $u$ = 0

Final velocity or $v$ = 72 km/hour

t = 5 minutes

Now,

Convert the time into hours to make the quantity proportional to the final velocity

As,

We know that

60 minutes = 1 hour

1 minute = 1/60 hour

So,

5 minutes = 5/60 hour

                 = 1/12 hour

Now,

acceleration = $\frac{v - u}{t}$

                     = 72 - 0 / 1/12

                     = 72 /  1/12

12 will go to the numerator

So,

acceleration = 72 / 1/12

                     = 72 X 12/1

                     = 864 km/$hour^{-2}$

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