Question

A bus starting from rest attains a velocity of 27km/h in 60seconds, itse acceleration;s??​

Answer 1

Explanation:

initial velocity(u)=0km/h

final velocity (v)=27km/h

time =60sec - 1/60

acceleration=v-u/t

a=27-0/1/60

a=27×60

a=144

hope this will help u...

Answer 2

Answer:

$[tex]As\ the\ bus\ started\ from\ rest;\ u\ =\ 0\\and,\ v\ =\ 27km h^{-1}\ =\ \frac{27 X 1000}{60 X 60}\ =\ 7.5ms^{-1}\\and, t\ = 60sec\\ As\ we\ know\ :-\ a\ = \frac{v-u}{t}\\a\ =\ \frac{7.5\ - 0}{60}\\ a\ = \frac{7.5}{60}\\ \implies a\ =\ 0.13m s^{2}$[/tex]

Explanation:

Hope it helps you :)