Question

a bus starting from rest attains a velocity of 54km/h in 60s. what is the acceleration

Answer 1

Initial velocity (u)= 0
Final velocity(v) = 54km/h
=15m/s
Time (t) = 60s
Let acceleration be a
As we know
a=(v-u)/t
=(15-0)/60
=15/60
= 1/4
= 0.25
So the acceleration will be 0.25m/s^2

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Acceleration=0.25\:m/}s^{2}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about a train starting from rest attains a velocity of 54 km/h in 60 secs.

• We have to find acceleration of bus.

$\green{\underline\bold{Given :}} \\ :\implies \text{Initial\:velocity(u)=0 m/s} \\ \\ :\implies \text{Final \: velocity (v)= 54 \: km/h} \\ \\ :\implies \text{Time = 60 \: sec} \\ \\ \red{\underline \bold{To \: Find : }} \\ :\implies \text{Acceleration= ?}$

• According to given question :

$\text{Final \: velocity} = 54 \times \frac{5}{18} =15 \: m/s \\ \\ \bold{Using \: first \: equation \: of \: motion : } \\ : \implies v = u + at \\ \\ : \implies 15 = 0 + a \times 60 \\ \\ : \implies 60 \times a = {15} \\ \\ : \implies a = \frac{15}{60} \\ \\ \green{ : \implies \text{a =0.25 \: m}/{s}^{2} }$