Question

A bus starting from rest attains a velocity of 54km\h in 60s,its acceleration is_____

Answer 1

Answer:0.25m/s^2

Explanation:

u=0m/s

v=54km/h=15m/s

t=60s

a=v-u/t

=15-0/60=15/60m/s

=1/4m/s^2 or 0.25m/s^2

Answer 2

Answer: Acceleration = 0.25m/s^2

Explanation:

From the question we know that,

Initial velocity,u = 0 m/s

Final velocity,v = 54 km/h

Time,t = 60 seconds

Now, convert final velocity in terms of m/s.

Final velocity = 54×5/18 = 15 m/s

Now apply this formula,

v = u + at

15 = 0 + a × 60

60 × a = 15

a = 15/60

a = 0.25 m/s^2.

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