Question

a bus starting from rest attains at a velocity 72km.p.h in 5 minutes. if the acceleration is uniform, its acceleration is in m/s2​

Answer 1

Answer:

a= 0.15 m/s^2

Explanation:

Given : u=0

v=72 km/hr

=72×5/18 = 45 m/s. ( 1kmph = 5/18 mps)

t= 5 mins = 5×60 s = 300s

a= v-u/t

a = 45-0/300

= 45/300

a= 0.15m/s^2

Answer 2

A bus starting from rest means (u = 0) attains at a velocity 72km/h means (v = 72 km/h) in 5 min means (t = 5 min) and we have to find the acceleration in m/s².

Given :

• Initial velocity (u) = 0 m/s
• Final velocity (v) = 72 km/h = (72 × 5/18) = 20 m/s
• Time (t) = 5 min = (5 × 60) = 300 s.

To Find :

• Acceleration (a) = ?

Solution :

Using Formula : v = u + at

$\longrightarrow$ 20 = 0 + a(300)

$\longrightarrow$ 20 = 300a

$\longrightarrow$ 20/300 = a

$\longrightarrow$ a = 0.066

Hence the acceleration of the bus is 0.066 m/s².