A bus starting from rest masses with a uniform acceleration of 2 m/s for 4 minutes. a)find the speed acquired. b)find the distance travelled
Answers
Explanation:
The first term is, 4a2 its coefficient is 4 .
The middle term is, -13a its coefficient is -13 .
The last term, "the constant", is +10
Step-1 : Multiply the coefficient of the first term by the constant 4 • 10 = 40
Step-2 : Find two factors of 40 whose sum equals the coefficient of the middle term, which is -13 .
-40 + -1 = -41
-20 + -2 = -22
-10 + -4 = -14
-8 + -5 = -13 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -8 and -5
4a2 - 8a - 5a - 10
Step-4 : Add up the first 2 terms, pulling out like factors :
4a • (a-2)
Add up the last 2 terms, pulling out common factors :
5 • (a-2)
Step-5 : Add up the four terms of step 4 :
(4a-5) • (a-2)
Which is the desired factorization