Question

A bus starting from rest moves with a uinform acceleration of 0.1 ms^-2for 2 minutes . Find (a) the speed acquired . (b) the the distance travelled.

Answer 1

Answer:

• Speed acquired = 12m/s
• Distance travelled = 720 m

Answer 2

Answer :-

v = 12 m/s

s = 720 m

Given :-

u = 0 m/s

a = 0.1 m/s²

t = 2 minutes

= 2 × 60

= 120 s

To find :-

The speed acquired and the distance travelled.

Solution :-

The speed acquired by the body is calculated by using first equation of motion:-

$\huge \boxed{v = u + at}$

Put the given value,

→$v = 0 + \dfrac{1}{10} \times 120$

→$v = 12 m/s$

hence,

The speed acquired by bus is 12 m/s.

Distance travelled by bus is given by third equation of motion:-

$\huge \boxed{2as = v^2 - u^2}$

→$2 \times \dfrac{1}{10}\times s = (12)^2 - (0)^2$

→$\dfrac{s}{5} = 144$

→$s = 144 \times 5$

→$s = 720 m$

hence,

Distance travelled by bus is 720 m.