Question

A bus starting from rest moves with a uniform acceleration of 0.1 m/s2 for 2mins. Find the
speed acquired and the distance travelled.​

Answer 1

u=0 m/s

v=?

a=0.1 m/s^2

t=2 minutes=120 seconds

Now, For Speed acquired

v=u+at

=0+0.1×120

=12m/s

And, For distance travelled,

s=ut+1/2at^2

=0×120+1/2×0.1×14400

=720 metres

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Answer 2

Given:

initial velocity, u = 0 m/s (rest)

acceleration, a = 0.1 m/s²

time = 2 min = 2 × 60s = 120s

By using Newton's first equation of motion:

v = u + at [where, v is the final velocity]

=> v = 0 + 0.1 × 120

=> v = 12 m/s

Now, using Newton's third equation of motion:

2as = v² - u² [where, s is the distance]

s = $\rm\frac{v^2 - u^2}{2a}$

s = $\rm\frac{(12)^2 - (0)^2}{2×0.1}$

s = $\rm\frac{144}{0.2}$

s = $\rm\frac{1440}{2}$

$\rm\fbox{ s = 720 m }$

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(Answered on 23rd Jan)