Question

A bus starting from rest moves with a uniform acceleration of 0.1 m s-2 for 2 minutes. Find (a) the speed acquired, (b) the distance travelled.

NCERT Class IX
Sciences - Main Course Book

Chapter 8. Motion

Answer 1

u = 0,      a = 0.1 m/sec²        t = 120 sec = 2minutes

equation of motion :  v = u + a t = 0 + 0.10 * 120 = 12 m/sec

s = u t + 1/2 a t² = 0 + 1/2 * 0.10 * 120² = 720 meters

Answer 2

Answer:

Explanation:

Given :-

Initial speed of the bus = 0 m/s

Acceleration = 0.1 m/s²

Time taken, t = 2 minutes = 120 s

To Find :-

(a) Speed acquired,

(b) Distance travelled.

Solution :-

Putting all the value, we get

(a) Speed acquired

⇒ v = u + at

⇒ v = 0 + 0 × 1 × 120

⇒ v = 12 m/s

(b) Distance travelled.

⇒ (12)² - (0)² = 2(0.1) s

⇒ s = 720 m

Hence, Speed acquired finally by the bus is 12 m/s.

And Distance travelled by the bus is 720 m.