A bus starting from rest moves with a uniform acceleration of 0.3m/s for 6 min .
Find its a) speed acquired b) distance travelled
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Answer:
Distance = 19440 m
Speed = 54 m/s
Explanation:
u = 0
a = 0.3 = 3/10
t = 6 min = 360s
From equations of motion
s = ut + 1/2 at ^ 2
Since u = 0
= 1/2 at ^ 2
= 1/2 × 3/10 × 360 × 360
= 54 × 360
= 19440 m
Now,
Speed = Distance / Time
= 19440 / 360
= 54 m/s
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