Question

A bus starting from rest moves with a uniform acceleration of 0.25m/s^2 for 2min then speed acquired by bus in 2min will be

Answer 1

Explanation:

Accelaration = 0.25

Time taken =2 min = 120 sec

Final speed = ?

$a = \frac{ (v - u) }{t}$

where v is final velocity

and u is initial velocity

applying this formula to our data, we get,

$0.25 = \frac{v - 0}{120}$

u is 0 as the bus starts from rest

From this we get...

120×0.25 = v

30 = v

So the final velocity of the bus after 2 min is

30 m/s

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