Question

A bus starting from rest moves with a uniform acceleration of 0.1m/s2 for 2 minutes find(1)the speed acquired (2)the distance travelled

Answer 1

Answer:

distance =12

and speed =10km/h

Answer 2

Answer:

(1)the speed acquired= 12m/s

(2)the distance travelled=720m.

Explanation:

Given Information -

• Initial velocity (u) = 0m/s
• Acceleration (a) = 0.1 m/s²
• Time = 2 mins = 120 s.

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Required Solutions-

• (1)the speed acquired(final velocity = v)
• (2)the distance travelled.

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Solution -

$\pink\bigstar$(1)$\underbrace\mathscr\red{Finding\:Final\:Velocity(v)-}$

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$\implies$ Formula- v=u+at

$\implies$ Answer-$v = 0 + (120 \times \frac{1}{10} ) \\ \\ v = 0 + 12 \\ \\ v = 12$

So here, the final velocity is 12m/s.

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$\purple\bigstar$(2)$\underbrace\mathscr\red{Finding\:Distance(s) -}$

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$\implies$ Formula-${s=ut+\frac{1}{2}at² }$

$\implies$ Answer-$= (0 \times 120) + \frac{1}{2} \times \frac{1}{10} \times {120}^{2} \\ \\ = 0 + \frac{1}{2} \times \frac{1}{10} \times 14400 \\ \\ = \frac{14400}{20} \\ \\ = 720$

Therefore, the distance is 720m.