Question

A bus starting from rest moves with a uniform acceleration for 2 minutes. If the velocity at the end of 2 minutes is 12 m/s, its acceleration is *

Answer 1

Answer:

u=0

v=12m/s

t=120sec

a=v-u/t

12-0/120=

12/120=0.01m/s

Answer 2

Answer:

0.1 m/s²

Explanation:

Given :

• Initial velocity = u = 0 m/s

• Time taken = t = 2 minutes = 120 seconds

• Final velocity = v = 12 m/s

To find :

• Acceleration of the bus

Acceleration = (v-u)/t

Acceleration = (12-0)/120

Acceleration = 12/120

Acceleration = 1/10

Acceleration = 0.1 m/s²

The acceleration of the bus is equal to 0.1 m/s², which means the bus will increase its velocity by 0.1 m/s every second