Question

a bus starting from rest moves with a uniform acceleration of 0.6m/s for 6 minutes find the speed acquired and distance travelled ​

Answer 1

Step-by-step explanation:

Given :-

Initial speed of the bus = 0 m/s

Acceleration = 0.1 m/s²

Time taken, t = 2 minutes = 120 s

To Find :-

(a) Speed acquired,

(b) Distance travelled.

Solution :-

Putting all the value, we get

(a) Speed acquired

⇒ v = u + at

⇒ v = 0 + 0 × 1 × 120

⇒ v = 12 m/s

(b) Distance travelled.

⇒ (12)² - (0)² = 2(0.1) s

⇒ s = 720 m

Hence, Speed acquired finally by the bus is 12 m/s.

And Distance travelled by the bus is 720 m.

Answer 2

Answer:

distance=38.88km, speed=108m/s

Step-by-step explanation:

By second eq of motion

s=ut+(at^2)/2

=0+(0.6*360*360)/2

3880m

distance=38.88km

Speed=distance/time

=3880/360

=108m/s Ans

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