Question

A bus starting from rest moves with a uniform acceleration of 0.5 m/s2 for 10 seconds. Find the distance traveled in the time interval. *

Answer 1

Answer:

s = ut + 1/2 at2

= 0 (10) + 1/2 (0.5) (10)^2

= 0 + 1/2 (50)

= 25 m

Explanation:

Hope it helps you mate

Answer 2

Given :

➛ Initial velocity = zero (i.e., rest)

➛ Acceleration = 0.5m/s²

➛ Time of journey = 10s

To Find :

➨ Distance covered by bus in the given interval of time.

Concept :

➠ Since, acceleration has said to be constant throughout the motion, we can easily apply equation of kinematics to solve this question.

✭ Second equation of kinematics :

• s = ut + (1/2)at²

where,

◕ s denotes distance

◕ u denotes initial velocity

◕ a denotes acceleration

◕ t denotes time

Calculation :

⇒ s = ut + (1/2)at²

⇒ s = (0 × 10) + (1/2)[0.5 × (10)²]

⇒ s = 0 + (0.5 × 0.5 × 100)

⇒ s = 25m