Question

A bus starting from rest moves with a uniform acceleration of 0.5 m/s2 for 10 seconds. Find the distance traveled in the time interval. ​

Answer 1

☞Given :

• Initial velocity = zero (i.e., rest)
• Acceleration = 0.5m/s²
• Time of journey = 10s

☞To Find :

• Distance covered by bus in the given interval of time.

☞Concept :

➠ Since, acceleration has said to be constant throughout the motion, we can easily apply equation of kinematics to solve this question.

✭ Second equation of kinematics :

s = ut + (1/2)at²

where,

• s denotes distance
• u denotes initial velocity
• a denotes acceleration
• t denotes time

☞Calculation :

⇒ s = ut + (1/2)at²

⇒ s = (0 × 10) + (1/2)[0.5 × (10)²]

⇒ s = 0 + (0.5 × 0.5 × 100)

⇒ s = 25m

Answer 2

Explanation:

a=0.1m/s 2

and t=2min=120s

(A)v=u+at=0+0.1×120

⟹v=12m/s

(b)s=ut+

21 at 2

⟹s=0+ 21

×0.1×(120) 2

⟹s=720m