Question

A bus starting from rest moves with a uniform acceleration of 0.1 m s
-2 for 2
minutes. Find (a) the speed acquired, (b) the distance travelled.

Answer 1

Explanation:

given

acceleration = 0.1 ms^-2

time = 2 minutes

. ie = 120 s

(a)

speed = acceleration × time

= 0.1 × 12o

= 12 ms^-1

(b)

distance = speed × time

= 12 × 120

= 1440 m

NOTE:

In uniform acceleration velocity is constant

Answer 2

Given :

• Initial velocity, u = 0 m/s
• Acceleration, a = 0.1 m/s²
• Time, t = 2 minutes

To find :

• Speed acquired &
• Distance travelled

According to the question,

Note : We will change 2 minutes into seconds

• 2 × 60 = 120 seconds

By using Newtons first equation of motion and we can find distance by using Newtons second equation of motion,

→ v = u + at

Where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• t = Time

→ v = 0 + 0.1 × 120

→ v = 0 + 12

→ v = 12

So,the speed acquired is 12 m/s.

b)

→ s = ut + ½ at²

→ s = 0 × 120 + ½ × 0.1 × 120 × 120

→ s = 0 + ½ × 0.1 × 14400

→ s = 0 + ½ × 1440

→ s = 0 + 720

→ s = 720

So,the distance travelled is 720 metres.

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