Question

a bus starting from rest moves with a uniform acceleration of 0.1m powersec -2for 2min. find the speed acquired the distance travelled <br />

Answer 1

u=0
a=0.1
t=2min=120sec
v=u+at
=0+(0.1×120)
v=12 m/sec

2as=v^2 - u^2
2×0.1×s=12^2 - 0^2
s=144/(0.2)
s=720m

Answer 2

Answer:

Given

Initial velocity (u) = 0 {rest position}Acceleration (a) = 0.1m/s²time taken (t) = 2min = 2 × 60 = 120s

To Find

Distance travelled

Solution

As we know that

→ s = ut + ½ at² {2nd equation of motion }

→ s = 0 × 120 + ½ × 0.1 × 120 × 120

→ s = 0.1 × 60 × 120

→ s = 720m

Hence,

Distance travelled by bus is720m

Extra Information

Force = mass × accelerationv = u + at {First equation of motion}v² = u² + 2as {third equation of motion}Pressure = Force/Area