Question

A bus starting from rest moves with a uniform acceleration of 0.1.ms-² for two minutes. find the speed acquired​

Answer 1

Answer:

12 m/s

Explanation:

As per the provided information in the given question, we have :

• Acceleration (a) = 0.1 m/s²
• Time (t) = 2 minutes

We are asked to calculate the speed acquired, i.e its final velocity (v).

>> Here, as the bus started from rest, so it's initial velocity (u) can be considered as 0 m/s.

Before commencing the steps to find the answer, it must be insured that the time should be in seconds.

⇒ 1 minute = 60 seconds

⇒ 2 minutes = (60 × 2) seconds

⇒ 2 minutes = 120 seconds

>> Time (t) = 120 seconds

Now, we can calculate the final velocity by using two ways.

First way is by using the formula of acceleration.

$\longrightarrow \sf {a= \dfrac{v-u}{t} }$

• a denotes acceleration
• v denotes final velocity
• u denotes initial velocity
• t denotes time

$\longrightarrow \sf {0.1= \dfrac{v-0}{120} }$

$\longrightarrow \sf {\dfrac{1}{10} \times 120=v-0 }$

$\longrightarrow \sf {1 \times 12=v}$

$\longrightarrow \sf { 12=v}$

$\longrightarrow\underline{\boxed{ \sf { 12 \; m/s=Speed\; acquired}} }\; \bigstar$

$\therefore$ Speed acquired by the bus is 12 m/s.

Second way is by using the first equation of motion.

$\longrightarrow \sf {v = u + at}$

• a denotes acceleration
• v denotes final velocity
• u denotes initial velocity
• t denotes time

$\longrightarrow \sf {v = 0 + ( 0.1 \times 120) }$

$\longrightarrow \sf {v = 0 + 12}$

$\longrightarrow \sf { v=12}$

$\longrightarrow\underline{\boxed{ \sf { 12 \; m/s=Speed\; acquired}} }\; \bigstar$

$\therefore$ Speed acquired by the bus is 12 m/s.