a bus starting from rest moves with a uniform acceleration of 0.1 m a from 2 minutes find the speed acquired and distance Travels
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Answered by
3
Given,
Initial velocity(u)="0m/s"Accelaration(a)="0,1m/s-2"Time="2 mins=60*2=120 secs"Final velocity=?
v=u+atv=0+(0.1)120v=0+12v=12m/si.e Final Velocity="12m/s"Distance(s)=v(v)-u(u)=2as=144-0=2(0.1)s=144=0.2s=1440=2s=720m Therefore,Speed Aqquired=12m/sDistance Travelled=720m
Hope this answer helps You. If you like please mark it brainliest :D
Initial velocity(u)="0m/s"Accelaration(a)="0,1m/s-2"Time="2 mins=60*2=120 secs"Final velocity=?
v=u+atv=0+(0.1)120v=0+12v=12m/si.e Final Velocity="12m/s"Distance(s)=v(v)-u(u)=2as=144-0=2(0.1)s=144=0.2s=1440=2s=720m Therefore,Speed Aqquired=12m/sDistance Travelled=720m
Hope this answer helps You. If you like please mark it brainliest :D
icantellmaddyman:
sorry didnt enter spaces was in a hurry
Answered by
1
Answer:
s = ut + 1/2at^2
s = 0 * 120s + 1/2 * 1/10m/s^2 * 120s
s = 1/2 * 12m
s = 6m
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