Question

A bus starting from rest moves with a uniform acceleration of 0.1 ms-2for 2 minutes. Find
a) the speed acquired b) the distance travelled

Answer 1

Answer:

v = 12 m/s

s = 720 m

Explanation:

As per the provided information in the given question, we have :

• Initial velocity (u) = 0 (As it starts from rest)
• Acceleration (a) = 0.1 m/s²
• Time taken (t) = 2 minutes

Conversion of units :

We've to convert minutes into seconds to find the required answer.

⇒ Time = 2 minutes

• 1 minute = 60 seconds

⇒ Time = (2 × 60) seconds

⇒ Time = 120 seconds

_________________________

We are asked to calculate the speed acquired (v) and the distance travelled (s).

Calculating speed acquired :

By using the first equation of motion,

★ v = u + at

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time

⇒ v = 0 + 0.1(120)

⇒ v = 0 + 12

⇒ v = 12 m/s

∴ Speed acquired is 12 m/s.

Calculating distance travelled :

By using the third equation of motion,

★ v² - u² = 2as

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• s denotes distance

⇒ (12)² - (0)² = 2 × 0.1 × s

⇒ 144 - 0 = 0.2s

⇒ 144 = 0.2s

⇒ 144 ÷ 0.2 = s

⇒ 720 m = s

∴ Distance covered by the object is 720 m.

$\rule{200}2$

More Information :

Equations of motion :

$\boxed{ \begin{array}{cc} \pmb{\sf{ \quad \: v = u + at \quad}} \\ \\ \pmb{\sf{ \quad \: s= ut + \cfrac{1}{2}a{t}^{2} \quad \: } } \\ \\ \pmb{\sf{ \quad \: {v}^{2} - {u}^{2} = 2as \quad \:}}\end{array}}$

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time
• s denotes distance