A bus starting from rest moves with a uniform acceleration of 0.1 m s² for 2 minutes. Find (a) the speed acquired, (b) the distance travelled
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Answered by
2
Answer:
Explanation:
speed acquired=2minutes*0.1m/s^2=120*1/10=12m/s
distance travelled=1440m
Answered by
4
Answer:-
Speed acquired finally by the bus is 12 m/s.
Distance travelled by the bus is 720 m.
Given:-
Initial speed of the bus, u= 0 m/s
Acceleration, a = 0.1 m/s²
Time taken, t = 2 min = 2×60 = 120 sec
(a) To find speed acquired, we use v= u + at
⇒ v= u + at
⇒ v= 0 + 0.1 × 120
⇒ v= 12 ms-1
(b) To find the distance travelled, we use v² - u² = 2as
s is the distance covered by the bus
⇒ (12)² - (0)² = 2(0.1) s
⇒ 144 = 0.2
⇒ s = 720 m
Speed acquired finally by the bus is 12 m/s.
Distance travelled by the bus is 720 m.
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