Question

A bus starting from rest moves with a uniform acceleration of 0.1 m/s^2 for 2 minutes find the speed and distance travel

Answer 1

u=0(bus starts from rest)
a=0.1m/s^2
t=2minutes=2*60=120 seconds
v=????(to be calculated)
s=?????(to be calculated)
$v = u + at \\ = 0 + 0.1 \times 120 \\ = 12$
$s = ut + \frac{1}{2}a {t}^{2} \\ = 0 \times 120 + \frac{1}{2} \times 0.1 \times 120 \times 120 \\ = 0 + 60 \times 12 \\ = 720$
So, speed is 12m/s.
And Distance Travelled is 720m.

Answer 2

u = 0m /sec. a = 0.1m/sec2. t = 2min
= 120sec
v = ? s = ?
v = u + at
v = 0 + 0.1*120
= 12m/sec
s = ut + 1/2at2
= 0*120 + 1/2*0.1*(120)^2
= 720m

Hope the answer is correct.........