Question

a bus starting from rest moves with a uniform acceleration of 0.1m/sec² for 2minutes. find the speed accqired and distance.
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Answer 1

⇝ Given :-

• A bus starting from rest moves with a uniform acceleration of 0.1 m/s² for 2minutes.

⇝ To Find :-

• The speed accqired and Distance traveled.

⇝ Solution :-

❒ Converting Time in Seconds :-

We Have,

$\text{Time= 2 mins}$

$= \rm( 2 \times 60)second$

$\red{:\longmapsto \text{Time = 120 \:s}}$

Here,

• Initial Velocity = u = 0 m/s

• Time Taken = t = 120 s

• Acceleration = a = 0.1 m/s²

1 》 Calculating Speed Acquired :-)

Let Speed Acquired by Car be = v m/s

❒ We Have 1st Equation of Motion as :

$\large \bf \red \bigstar \: \: \orange{ \underbrace{ \underline{v = u + at}}}$

⏩ Applying 1st Equation of Motion ;

$:\longmapsto \rm v = 0 + 0.1 \times 120$

$:\longmapsto \rm v = 0.1 \times 120$

$\purple{ \Large :\longmapsto  \underline {\boxed{{\bf v = 12} }}}$

Therefore,

$\large\underline{\pink{\underline{\frak{\pmb{\text Speed \: \text Acquired = 12m/s }}}}}$

2 》Calculating Distance Traveled :-)

❒ We Have 2nd Equation of Motion as :

$\large \bf \red \bigstar \: \: \orange{ \underbrace{ \underline{s=ut+\dfrac{1}{2}at^2}}}$

⏩ Applying 2nd Equation of Motion :

$:\longmapsto \rm s = 0 \times 120 + \frac{1}{2} \times 0.1 \times 102 {}^{2}$

$:\longmapsto \rm s = 0 + \frac{1}{2} \times 0.1 \times 14400$

$\purple{ \large :\longmapsto  \underline {\boxed{{\bf s = 720 \: m} }}}$

Therefore,

$\large\underline{\pink{\underline{\frak{\pmb{ Distance  \text Traveled = 720 \: m }}}}}$

Answer 2

Answer:

Question :-

• A bus starting from rest moves with a uniform acceleration of 0.1 m/s^2 for 2 minutes.Find the speed acquired and distance.

Answer :-

• Speed acquired =12 m/s.

• Distance travelled =720m.

Given :-

• A bus is starting from the rest moves with a uniform acceleration of 0.1m/s^2 for 2 minutes.

To find :-

• Speed acquired
• Distance travelled.

Explanation :-

• Here ,we should take
• Initial velocity =0 m/s.

• Here we first we should come to know that ,
• We should convert time in seconds in applying for the equation.
• So,
• Time=2minutes
• Time=2×60=120sec.

1》First we should find speed acquired by the bus.

• Consider speed acquired by the bus be =v m/s.
• Here to get answer we should Apply first equation of motion that is,

$v = u + at$

• Now applying all the values we get that,

• $v = 0 + 0.1 \times 120 = 12$

$\mathcal\purple{So,}$

• Speed acquired by the bus =12 m/s.

2》Finding distance travelled by the bus.

• Here we should apply second equation of motion we get that,

$s = ut + \frac{1}{2} a {t}^{2}$

• Now applying all the values we get that,

• $s = 0 \times 120 + \frac{1}{2} \times 0.1 \times {120}^{2}$
• $s = 0 + \frac{1}{2} \times 0.1 \times 14400 = 720m$

$\mathcal\red{Therefore ,}$

• Distance travelled by the bus=720m.

Hope it helps u mate.

Thank you .