Question

a bus starting from rest moves with a uniform acceleration of 0.1m/sec² for 2minutes. find the speed accqired and distance.
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Answer 1

Answer:

a=0.1m/s2

and t=2min=120s

(A)v=u+at=0+0.1×120

⟹v=12m/s

(b)s=ut+21at2

⟹s=0+21×0.1×(120)2

⟹s=720m

Answer 2

${\huge{\pink{↬}}} \: \: {\huge{\underline{\boxed{\bf{\pink{Answer}}}}}}$

⇝ Given :-

A bus starting from rest moves with a uniform acceleration of 0.1 m/s² for 2minutes.

⇝ To Find :-

The speed accqired and Distance traveled.

⇝ Solution :-

❒ Converting Time in Seconds :-

We Have,

$\text{Time= 2 mins}$

$= \rm( 2 \times 60)second$

$\red{:\longmapsto \text{Time = 120 \:s}}$

Here,

Initial Velocity = u = 0 m/s

Time Taken = t = 120 s

Acceleration = a = 0.1 m/s²

1 》 Calculating Speed Acquired :-)

Let Speed Acquired by Car be = v m/s

❒ We Have 1st Equation of Motion as :

$\large \bf \red \bigstar \: \: \orange{ \underbrace{ \underline{v = u + at}}}$

⏩ Applying 1st Equation of Motion ;

$:\longmapsto \rm v = 0 + 0.1 \times 120$

$:\longmapsto \rm v = 0.1 \times 120$

$\purple{ \Large :\longmapsto  \underline {\boxed{{\bf v = 12} }}}$

Therefore,

$\large\underline{\pink{\underline{\frak{\pmb{\text Speed \: \text Acquired = 12m/s }}}}}$

2 》Calculating Distance Traveled :-)

❒ We Have 2nd Equation of Motion as :

$\large \bf \red \bigstar \: \: \orange{ \underbrace{ \underline{s=ut+\dfrac{1}{2}at^2}}}$

⏩ Applying 2nd Equation of Motion :

$:\longmapsto \rm s = 0 \times 120 + \frac{1}{2} \times 0.1 \times 102 {}^{2}$

$:\longmapsto \rm s = 0 + \frac{1}{2} \times 0.1 \times 14400$

$\purple{ \large :\longmapsto  \underline {\boxed{{\bf s = 720 \: m} }}}$

Therefore,

$\large\underline{\pink{\underline{\frak{\pmb{ Distance  \text Traveled = 720 \: m }}}}}$