Question

A BUS STARTING FROM REST MOVES WITH A UNIFORM ACCELERATION OF 0.1 MS-2 FOR 2 MINUTES FIND THE SPEED ACQUIRED THE DISTANCE TRAVEELED

Answer 1

Answer:

Since a = 0.1 m.s-2,

v = 12 m.s-1,

u = 0 m.s-1, and

t = 120s,

the following value for s (distance) can be obtained.

Distance, s =(v2 – u2)/2a

=(122 – 02)/2(0.1)

Therefore, s = 720m.

The speed acquired is 12m.s-1 and the total distance traveled is 720m.

Answer 2

Answer:

720 meter

Explanation:

since, s= ut+1/2at^2

here, u = 0

a= 0.1 ms-2

t= 2 min = 120 sec

=> s = 0+ 1/2×0.1×(120)^2

= 1/2×0.1×14400

=720 m