A bus starting from rest moves with a uniform acceleration of 0.2 m/s square for 5 minutes in a circle. Calculate the speed acquired and the distance covered by the bus
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U = 0
t = 5 min. = 5 * 60 sec. = 300 Second
a = 0.2 m / s ^ 2
V = U + at
= 0 + 0.2 * 300
= 60 m / s Ans.
V ^ 2 - U ^ 2 / 2a = S
S = ( 60 ) ^ 2 - 0 / 2 * 0.2
= 3600 / 0.4
= 9000m
t = 5 min. = 5 * 60 sec. = 300 Second
a = 0.2 m / s ^ 2
V = U + at
= 0 + 0.2 * 300
= 60 m / s Ans.
V ^ 2 - U ^ 2 / 2a = S
S = ( 60 ) ^ 2 - 0 / 2 * 0.2
= 3600 / 0.4
= 9000m
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