Question

A bus starting from rest moves with a uniform acceleration of 0.1 m/s for 2 minutes find the speed acquired and the dustance travelled

Answer 1

u=0
A=0.1m\s
t=2min=120sec

v=u+at
v=0+0.1×120
v=12.0m/sec


s=ut+1/2a×t×t
s=0+1/2 ×0.1 ×120×120
s=720m

Answer 2

AnswEr:

Given,

• Initial velocity, u = p ms¹
• a = 0.1 $\sf{ms}^{-2}$
• t = 2 min

= 2 * 60

= 120 s

• Final Velocity, v = ?

$\star$ $\underline\text{Using\:\:first\:\:equation\:\:of\:\:motion:-}$

$\tt \: v = u + at \\ \tt \: v = 0 + 0.1 \times 120 \\ \\ \tt \: v = 12 \: {ms}^{ - 1}$

$\therefore$ Final Velocity is 12 $\sf{ms}^{-1}$

• For distance, we use second equation of motion

$\tt \: s = ut + \frac{1}{2} \: {at}^{2} \\ \\ \tt = s = 0 \times 120 + \frac{1}{2} \times 0.1 \times {(120)}^{2} \\ \\ \tt \: s = \frac{1}{2} \times 0.1 \times {(120)}^{2} \\ \\ \tt \: s = 720 \: m$

Therefore, distance will 720 m