A bus starting from rest moves with a uniform acceleration of 0.2 m s-2for 180 s. Calculate (a) speed acquired (b) distance travelled
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a= 0.2ms-2
t = 180s
u= 0ms-1
v= u + at
v= 0 + 0.2× 180
v= 36.0
v= 36ms-1
s= ut + 1÷2 at
s= 0 + 1÷2 × 0.2 × 180
s= 18m
t = 180s
u= 0ms-1
v= u + at
v= 0 + 0.2× 180
v= 36.0
v= 36ms-1
s= ut + 1÷2 at
s= 0 + 1÷2 × 0.2 × 180
s= 18m
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