A bus starting from rest moves with a uniform acceleration of 0.1m for 2 mins.Find(a)the speed required (b)the distance travelled.
Answers
Answer:
(a) velocity/time=acceleration
as we know 1min=60s
2min= 120s
acceleration=0.1m/s2
velocity=acceleration× time
= 0.1×120
= 12m/s= speed
(b) speed=distance/time
distance=speed×time
= 12× 120
=1440 m
→ Hey Mate,
→ Given Question:-
→ A bus starting from the rest moves with a uniform acceleration of 0.1m/s^2 for 2 min. Find (a) the speed required ,(b) the distance traveled.
→ To find: -
→ (a) speed required
→ (b) the distance traveled
→ Answer:-
→ Equations of motion :-
→ [ v = u + at ]
→ [ s = ut + 1/2at²]
→ [ v² = u² = 2as ]
→ u = 0
→ a = 0.1m/s
→ t = 2 min
→ 2 × 60
→ 120s
→ (a) v = ?
→ v = u + at
→ v = 0+ ( 0.1 × 120)
→ v = 12m/s
→ The speed is 12m/s.
→ ( b) s = ?
→ s = ut + 1/2 at²
→ ( 0 × t)² + 1/2 × 0.1 r( 20)²
→ 0.1 × ( 20 ) ² / 2 =
→ 720m
→ The distance travelled is 720m.
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