Question

A bus starting from rest moves with a uniform motion acceleration of 0.2 meter per second square for 4 minutes .what is the speed and distance.

Answer 1

Initial velocity of bus(u)= 0m/s
Let the final velocity of the bus be v.
acceleration=0.2m/s^2
time=4s
we know that a=(v-u)/t
0.2=v-0/4
0.2=v/4
v=0.8m/s

Now distance (s)=ut + 1/2 at^2
s=0*4+1/2*0.2*16
s=4 meters