Question

A bus starting from rest moves with a unoform acceleration of 0.1m/s square for 2 min find the speed aquired and the distance travelled

Answer 1

u=0

a=0.1m/s square

1.v=0

2.s=?

1.v=u+at

 v=0+0.1*120

 v=12 m/s

2.v square -u square=2as

   12 square-0 square=2*0.1*s

   144=0.2s

    s=144/0.2

     s=720

Answer 2

Answer:

Explanation:

Angle of repose is simply the angle of inclination for which friction is max. i.e. u=tan(theta). If angle of inclination is less than the max. angle then friction will b more as tan theta has nw bcm small due to smaller angle, if angle of inclination is more than the theta for max friction then the block will slide down as friction wont b enogh to stop that block. In ur qstion its said that block has to b pushed down so angle of inclination is less than the angle or thetafor max. friction do option C is correct. Its kind of messy wht i wrote but read it twice or more n also frm ur physics book or notes u ll get it. Its very simple.Hope it helps!!