Question

A bus starting from rest, moves with uniform acceleration.After 10 minutes its speed is 60Kmph

Answer 1

⇝ Given :-

• A bus starting from rest, moves with uniform acceleration

• After 10 minutes its speed is 60 Km/h

⇝ To Find :-

The speed accqired and Distance traveled.

⇝ Solution :-

❒ Converting Final Speed in m/s :-

We Have,

$\text{Final Speed=60 km/h}$

$= \rm( 60 \times\dfrac{5}{18} ) m/s$

$\red{:\longmapsto \text{Final Speed  = 16.67 \:m/s}}$

❒ Converting Time in Seconds :-

We Have,

$\text{Time= 10 mins}$

$= \rm( 10 \times 60)second$

$\red{:\longmapsto \text{Time  = 600 \:s}}$

Here,

• Initial Velocity = u = 0 m/s

• Time Taken = t = 600 s

• Final Velocity = v = 16.67 m/s

$\green\bigstar$ Let Acceleration of Bus = a m/s²

⏩ We Have 1st Equation of Motion as :

$\large \bf \red\bigstar \: \: \orange{ \underbrace{ \underline{v = u + at}}}$

✏ Putting Values In 1st Equation :

$:\longmapsto \rm 16.67 = 0 + a \times 600$

$:\longmapsto \rm 600a = 16.67$

$:\longmapsto \rm a = \frac{16.67}{600}$

$\purple{ \large :\longmapsto  \underline {\boxed{{\bf a = 0.027} }}}$

Therefore,

$\large\underline{\pink{\underline{\frak{\pmb{   \text Acceleration = 0.03 \: m/s² }}}}}$

Answer 2

APPROPRIATE QUESTIONS:-

A bus starting from rest, moves with uniform acceleration.After 10 minutes its speed is 60 Kmph. find it's acceleration

EXPLANATION:-

• Initial velocity(u)=0 m/s
• Final velocity(v)=60 kmph=60×5/18→16.67 m/s
• Time taken(t)=10×60→600 s
• Acceleration=?

Using 1st equation of motion:-

v=u+at

16.67=0+a600

16.67=600a

a=16.67/600

a=0.027 m/s²

So the acc. is 0.027 m/s²

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