Question

a bus starting from rest moves with uniform acceleration of 0.1m/s square for 2 minutes. find
a) the speed acquired
b) the distance travelled​

Answer 1

Hey Pretty Stranger!

a) Speed Acquired :

• Initial Velocity (u) = 0 m/s

• Final Velocity (v) = ?

• Acceleration (a) = 0.1 m/s²

• Time (t) = 2 minutes = 120 seconds

From 1st equation of motion :

★ v = u + at

→ v = 0 + (0.1)(120)

→ v = 0 + 12

→ v = 12 m/s

$\therefore$ Speed acquired is 12 m/s

b) Distance Travelled :

From 3rd equation of motion :

★ v² = u² + 2as

→ (12)² = (0)² + 2(0.1)(s)

→ 144 = 0 + 0.2s

→ 144 - 0 = 0.2s

→ 144 = 0.2s

→ s = $\sf\dfrac{144}{0.2}$

→ s = 720 metres

$\therefore$ Distance travelled is 720 metres.

Answer 2

Given :-

• Initial velocity of bus (u)= 0 [ start from rest]

• Acceleration (a) = 0.1m/s^2

• Time (t) = 2 min = 2×60 = 120 seconds

To find :-

• The speed acquired

• Distance travelled .

Solution :-

By using 1st equation of motion , find the speed acquired

$\longrightarrow\sf v= u+at\\ \\ \longrightarrow\sf v= 0+0.1\times 120\\ \\ \longrightarrow\sf v= 12m/s$

$\underline{\bigstar{\sf\ Speed \ acquired= 12m/s}}$

Now , the distance travelled :-

By 3rd equation of motion

$\longrightarrow\sf v^2= u^2+2as\\ \\ \longrightarrow\sf (12)^2= (0)^2+2\times 0.1\times s\\ \\ \longrightarrow\sf 144= 0.2\times s\\ \\ \longrightarrow\sf \cancel{\dfrac{144}{0.2}}= s\\ \\ \longrightarrow\sf 720= s$

$\underline{\bigstar{\sf\ Distance \ travelled :- \ 720m }}$