Question

a bus starting from rest moves with uniform acceleration of 0.1m/s square for 2 minutes. find
a) the speed acquired
b) the distance travelled​

Answer 1

speed= distance/time

distance= time×speed

Answer 2

$\;\;\underline{\textbf{\textsf{ Given:-}}}$

• Initial velocity of bus, u= 0 m/s

• Acceleration, a = 0.1m/s²

• Time (t) = 2 min or 120 sec

$\;\;\underline{\textbf{\textsf{ To Find :-}}}$

• Speed required, v

• Distance travelled , s

$\;\;\underline{\textbf{\textsf{ Solution :-}}}$

$\underline{\:\textsf{ Using 1st equation of motion :}}$

$\dashrightarrow \sf v= u+at\\ \\ \dashrightarrow \sf v= 0+0.1\times 120\\ \\ \dashrightarrow \sf v= 12m/s$

ㅤ$\;\;\underline{\textbf{\textsf{ Hence-}}}$

$\underline{\textsf{ Required speed </p><p>\textbf{ 12m/s}}}.$

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Again,

$\underline{\:\textsf{ Using 3rd equation of motion :}}$

$\dashrightarrow \sf v^2= u^2+2as\\ \\ \dashrightarrow \sf (12)^2= (0)^2+2\times 0.1\times s\\ \\ \dashrightarrow \sf 144= 0.2\times s\\ \\ \dashrightarrow \sf \cancel{\dfrac{144}{0.2}}= s\\ \\ \dashrightarrow \sf 720= s$

ㅤ$\;\;\underline{\textbf{\textsf{ Hence-}}}$

$\underline{\textsf{ Distance travelled </p><p>\textbf{720 m}}}.$

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