a bus starting from rest moves with uniform acceleration of 0.1 m n square for 2 minutes. Find(i) the speed acquired(ii) the distance travelled
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Answered by
1
solution
vi=0m/s
a=0.1m/s^2
t=2min=2×60=120sec
using kinematic equation
vf=vi+at
vf=0+(0.1)(120)
vf=12m/s
s=vit+1/2at^2
s=(0)(120)+1/2 (0.1)(120)^2
s=720m
vi=0m/s
a=0.1m/s^2
t=2min=2×60=120sec
using kinematic equation
vf=vi+at
vf=0+(0.1)(120)
vf=12m/s
s=vit+1/2at^2
s=(0)(120)+1/2 (0.1)(120)^2
s=720m
Answered by
0
We can found ans. by first eq. of motion.
v=u+at.
v=?
u=0. (as the bus starting from rest initial speed is 0)
a=0.1msq. per second
v=u+at
v=0+0.1×120
v=12m/s
2)s=ut+1/2at²
s=0×120+1/2×0.1 ×14400
s=720m
pls mrk brainliest
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