Question

a bus starting from rest moves with uniform acceleration of 0.1 ms -2 for 2 minutes. find spped aquired and the distance travelled

Answer 1

a = 0.1 m/s²

u = 0 m/s

t = 2minutes = 120s

v = u + at

v = 0 + 0.1 × 120

v = 12 m/s

2as = v² - u²

2×0.1×s = 12²

0.2s = 144

s = 144/0.2

s = 720m

Answer 2

$\bold{\tt\purple{Answer : }}$

Given:-

⇒ Initial velocity,u = 0 m/s [ Bus starts from rest ]

⇒ Acceleration,a = 0.1 m/s²

⇒ Time taken,t = 2 minutes

To be calculated:-

calculate:(a) the speed acquired and (b) the distance travelled.

Solution:-

Time taken = 2 minutes

= 2 × 60 seconds

= 120 seconds

Now,

( a )

From the first equation of motion

⇒ v = u + at

★ Substituting the values in the above formula,we get:

⇒ v = 0 + 0.1 × 120

⇒ v = 1/10 × 120

⇒ v = 1 × 12

⇒ v = 12 m/s

Thus,the speed acquired by bus is 12 m/s.

( b )

From the second equation of motion,

⇒ s = ut + 1/2 at²

★ Substituting the values in the above formula,we get:

⇒ s = 0 × 120 + 1/2 × 0.1 × ( 120 )²

⇒ s = 0 + 1/2 × 1/10 × 14400

⇒ s = 1/2 × 1 × 1440

⇒ s = 1/2 × 1440

⇒ s = 720 m

Thus,the distance covered by the bus is 720 m.

$\bold{\tt\pink{Thanks}}$