A bus starting from rest moves with uniform motion acceleration of 0.1m/sec for 2 min. Its speed will be 1= 0.2m/sec
2= 0.12m/sec
3= 12.0m/sec
4= 1.20m/sec
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Explanation:
let the speed be velocity
initial velocity = u = 0m/s
final velocity = v
time = 2min = 120s
acceleration = 0.1m/s^2
a = ( v - u )
t
0.1 = ( v - 0 )
120
( v - 0 ) = 0.1 ( transposing )
120
v - 0 = 0.1×120
v = 12
therefore the final velocity ( speed ) will be 12m/s
your answer is option 3
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