Question

A bus starting from rest moves witha unform acceleration of 0.1m/sec square for2 minutes .find speed and distance travelled.

Answer 1

Answer:-

Here, initial speed, u = 90 kmh-1 = 90 x(5/18)  = 25 ms-1
Acceleration, a = – 0.5 ms-2

Train brought to rest, so final speed, v = 0
From third equation of motion, v2 = u2 + 2as
0 = (25)2 + 2 x 0.5 x s
0 = 625 – s
s = 625 m



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This is your answer of bus starting from rest moves witha unform acceleration of 0.1m/sec square for2 minutes .find speed and distance travelled.

Answer 2

u=0
a=0.1m/s²
t=2min=120s
a=v-u/t
1/10=v-0/120
120/10=v-0
12=v
12m/s=v

according to third law of motion...
2as=v²-u²
2*1/10*s=12²-0²
1/5*s=144-0
s=144*5
=720m