A bus starting from rest moving with a uniform acceleration of 0.1 metre second square for 2 minutes a.) find speed acquired b.) distance travelled and in this time
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Hey.
Here is the answer.
u = 0
a = 0.1 m/s^2
t = 2 minutes = 2×60 =120 s
a) as V = u + a t
so, speed acquired, v = 0 + 0.1×120= 12m/s
b) distance travelled in this time ,
s = u t + 1/2 a t ^2
or, s = 0 + 1/2 ×0.1× 120^2 = 720 m
Thanks
Here is the answer.
u = 0
a = 0.1 m/s^2
t = 2 minutes = 2×60 =120 s
a) as V = u + a t
so, speed acquired, v = 0 + 0.1×120= 12m/s
b) distance travelled in this time ,
s = u t + 1/2 a t ^2
or, s = 0 + 1/2 ×0.1× 120^2 = 720 m
Thanks
Answered by
0
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➧ u ➾ 0
➧ a ➾ 0.1 m/s²
➧ t ➾ 2 min = 120s
a❱ V ➾ u + at
V ➾ 0.1 × 120
V ➾ 12 ms-¹ ...✔
b❱ v² - u² ➾ 2as
(12)² - (0)² ➾ 2 (0.1)s
s ➾ 720 m ...✔
_________ Thanks...✊
➧ u ➾ 0
➧ a ➾ 0.1 m/s²
➧ t ➾ 2 min = 120s
a❱ V ➾ u + at
V ➾ 0.1 × 120
V ➾ 12 ms-¹ ...✔
b❱ v² - u² ➾ 2as
(12)² - (0)² ➾ 2 (0.1)s
s ➾ 720 m ...✔
_________ Thanks...✊
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