Question

A bus starting from rest travel for 22nd at acceleration of 3.5 metre per second square find the distance covered by the bus

Answer 1

Given,
Initial velocity (u) =0 (since body at rest)
Time (t) =20secs
Acceleration (a) =3.5m/sec2

To find -Distance (s) =?

Solution :-
We know,
a=v-u/t. (first equation of motion)
=> 3.5=v-0/20
=> v=3.5*20
=>v=70

Again,
s=ut+1/2at² (second equation of motion)
=>s=0*20+1/2(3.5)(20)²
=>s=1/2*3.5*20*20
=>s=1*3.5*10*20
=>s=700

Therefore Distance (s) =700 m