Question

A bus starting from rest was with a uniform acceleration of of 0.1 m s -² for 2 minutes find (a). The speed acquride . (b). The distance travelled.
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Answer 1

Answer:

We know that,v=at

(a)here,v=?

so,

v=(0.1×2×60)m/s

=12 m/s

(b)s=?

s=vt

=(12×2×60)m

=1440m

=1.44km

Explanation:

hope it will help you.

Answer 2

Answer:

GIVEN=INITIAL VELOCITY OF BUS U=0M/S

ACCELERATION OF BUS A=0.1 MS-2

TIME OF MOTION T=2 MINUTES

=2*60 SECONDS=120 SECONDS

(a) FROM FIRST EQUATION OF MOTION

V=U+AT

=0+0.1*120=12MS-1

(b) FROM THIRD EQUATION OF MOTION: v square - y square=2as

(12) SQUARE -(0) SQUARE=2(0.1)S

S=144/0.2=720m