a bus starting from rest with a uniform acceleration of 0.1/s square
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speed acquired
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Answered by
7
Given,
Initial velocity(u)="0m/s"
Accelaration(a)="0,1m/s-2"
Time="2 mins=60*2=120 secs"
Final velocity=?
v=u+at
v=0+(0.1)120
v=0+12
v=12m/s
i.e
Final Velocity="12m/s"
Distance(s)=v(v)-u(u)=2a
s=144-0=2(0.1)
s=144=0.2
s=1440=2
s=720m
Therefore,
(a)=12m/s
(b)=72
Initial velocity(u)="0m/s"
Accelaration(a)="0,1m/s-2"
Time="2 mins=60*2=120 secs"
Final velocity=?
v=u+at
v=0+(0.1)120
v=0+12
v=12m/s
i.e
Final Velocity="12m/s"
Distance(s)=v(v)-u(u)=2a
s=144-0=2(0.1)
s=144=0.2
s=1440=2
s=720m
Therefore,
(a)=12m/s
(b)=72
Where is time mentioned in question??
time is 5minute
Answered by
3
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