Question

A bus starting from rrst moves eith a uniform acceleration of 0.1m/s^2 for 2min.find a)the speed acquired. b)the distance yravelled.

Answer 1

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Initial Velocity (u) = 0 m/s

Acceleration (a) = 0.1 m/s²

Time (t) = 2 min = 2 × 60 = 120 s

By using 1st equation of motion we get :

⇒ v = u + at

⇒ v = 0 + (0.1)(120)

⇒ v = 0 + 12

⇒ v = 12 m/s

Hence , Speed aquired by bus is 12 m/s.

Now, Apply 3rd equation of motion ,

⇒ v² - u² = 2as

⇒ (12)² - (0)² = 2(0.1)s

⇒ 144 = 2(0.1)s

⇒ 0.1s = 72

⇒ s = 720 m

Hence, Distance traveled by bus is 720 m.