Question

A bus starting from the rest moves with a uniform acceleration of 0.1m/s^2 for 2 min.
Find (a) speed required
(b) the distance traveled

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Answer 1

→ Hey Mate,

→ Given Question:-

→ A bus starting from the rest moves with a uniform acceleration of 0.1m/s^2 for 2 min. Find (a) speed required ,(b) the distance traveled.

→ To find: -

→  (a) speed required

→  (b) the distance traveled

→ Answer:-

→ Equations of motion :-

→ [ v = u + at         ]

→ [  s = ut + 1/2at²]

→ [ v² = u² = 2as ]

→ u = 0

→ a = 0.1m/s

→ t  = 2 min

→ 2 × 60

→ 120s

→ (a)  v = ?

→ v = u + at

→ v = 0+ ( 0.1 × 120)

→ v = 12m/s

→ The speed is 12m/s.

→ ( b) s = ?

→ s = ut + 1/2 at²

→ ( 0 × t)² + 1/2 × 0.1 r( 20)²

→ 0.1 × ( 20 ) ² / 2 =

→ 720m

→ The distance travelled is  720m.

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Answer 2

Answer:

Given :-

Initial speed of the bus = 0 m/s

Acceleration = 0.1 m/s²

Time taken, t = 2 minutes = 120 s

To Find :-

(a) Speed acquired,

(b) Distance travelled.

Solution :-

Putting all the value, we get

(a) Speed acquired

⇒ v = u + at

⇒ v = 0 + 0 × 1 × 120

⇒ v = 12 m/s

(b) Distance travelled.

⇒ (12)² - (0)² = 2(0.1) s

⇒ s = 720 m

Hence, Speed acquired finally by the bus is 12 m/s.

And Distance travelled by the bus is 720 m.

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